If the diameter of the sphere is increased by 20% . by what % does its curved surface area increase?

Curved surface area of sphere = 2πr × 2r=4πr^2;

The new diameter is 120/100 from the old diameter;

2R = (120/100)x(2r);

So, R = 1.2 x r;

Curved surface area of new sphere = 4πR^2 = 4π(1.2xr)^2= 4πr^2x1.44= curved surface of old sphere x (144%);

Finnaly, the increase is 44%.

Step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right