Mathematics, 11.10.2019 06:40 jennsou

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write the standard form equation for the circle whose center is at (-2, 3) and that is tangent to the line 20x - 21y - 42 = 0.

a). x^2 - 4x + y^2 + 6y - 12 = 0
b). x^2 + 4x + y^2 - 6y - 12 = 0
c). x^2 + 4x + y^2 - 6y - 25 = 0

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Will award brainliest!
write the standard form equation for the circle whose center is at (-2...