Xy + 3ey = 3e, find the value of y'' at the point where x = 0.

y = 1

Step-by-step explanation:

If the equation is:

x*y + 3*e^y = 3*e

where x and y are variables, and e is a real number, we have that when x = 0, the value of y must be:

0*y + 3*e^y = 3*e

3*e^y = 3*e

(3*e^y)/(3*e) = 1

e^(y - 1) = 1

we know that any number A, when we have A^0 = 1

so here we have that y must be equal to 1

so y = 1

positive

step-by-step explanation:

the quadrant is facing upwards