Approximate the real zeros to the nearest tenth -x^2+x+4

The zeros of the given expression at x = -1.6 and x = 2.6

Step-by-step explanation:

Given: -x^2 + x + 4

To find the real zeros set the expression equal to zero and solve for x.

-x^2 + x + 4 = 0

This cannot be factored.

Let's use the quadratic formula and find the solutions.

Formula x =

Here a = -1, b = 1 and c = 4 from the given expression.

Now let's plug in these values in the above formula, we get

x =

x =

x = (-1 +/- )/-2                   [√17 = 4.1]

x = (-1 + 4.1)/ -2    and x = (-1 -4.1)/-2

x = 3.1/-2 and x = -5.1/-2

x = -1.55 and x = 2.55

When we round off to the nearest tenths place, we get

x = -1.6 and x = 2.6

Therefore, the zeros of the given expression at x = -1.6 and x = 2.6.

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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet