Soybean mean is 14% protein; cornmeal is 7% protein. how many pounds of each should be mixed together in order to get 280-lb mixture that is 13% protein?

I have to form a couple of equations in order to solve it.

let the amount of soybean in the mixture be x and that of cornmeal be y

Step-by-step explanation:

x+y = 280

y = 280 - x

x*(14/100) + y*(7/100) = 280*(12/100)

Multiplying the whole equation by 100;

14x + 7y = 3360

in this equation,put y = 280 - x

14x +7 (280-x) = 3360

14x +1960 - 7x = 3360

14x - 7x = 3360 - 1960

7x = 1400

x = 200lbs

y = 280 - x

= 280 - 200

= 80 lbs

Inorder to make a 280lbs mixture having 12% protein, we should mix 200lbs of soyabean and 80 lbs of cornmeal

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.