Aplot of land doubles in size by adding x meters to the length and x meters to the width of the land. if the original plot had an area of 200 x 300 m, what is the value of x?

x=100

Step-by-step explanation:

Original plot

A = 200*300

A = 60000

New plot

The new length is 200+x and the new width is 300+x

A = (200+x) (300+x)

It doubles the area = 60000*2 = 120000

120000 = (200+x) (300+x)

We need to find x

FOIL

120000 = 60000 +300x+200x +x^2

120000 = 60000 +500x +x^2

Subtract 120000 from each side

120000-120000 = 60000-120000 +500x +x^2

0 = x^2 +500x - 60000

Factor

0= (x-100) (x+600)

Using the zero product property

x=100 or x=-600

Since we cannot add negative land

x=100

goog may have it for you

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)