Pls will give brainliest, thx, and 5star

Solve 2^x=32 and rewrite this equation in a logarithmic form

Worth 100 points need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than 2 x is greater than 2 x is less than or equal to 2 x is greater than or equal to 2 second row -5 -5/2 4 5 •2 is less than x& x is less than 4 •2 is less than or equal to x & x is less than or equal to 4 •2 is less than or equal to x& x is less than 4 •2 is less than x& x is less than or equal to 4

What are the solutions for the following system? -2x^2+y=-5 y=-3x^2+5