50 points, 3 questions and explain your answer

See below.

Step-by-step explanation:

Two

Up to the fourth line is correct. The fifth line contains the error.

Line four take the square root of both sides.

sqrt(x-3)^2 = sqrt(16)

x - 3 is correct = +/- 4

x - 3 = 4

x = 3 + 4

x = 7

x - 3 = - 4

x = -4 + 3

x = - 2

The two answers should be (7,0) and (-2,0)

Three

x^2 - 4x + 3 = 0

This equation factors without the use of the quadratic formula

(x - 3)(x - 1) are its two factors.

So the two points are (3,0)(1,0). However I will be obedient to what you were asked for

a = 1

b = -4

c = 3

x  = [- b +/- sqrt(b^2 - 4ac)] / (2a)

x = [ -(-4) +/- sqrt(4^2 - 4(1)(3)]/(2*1)

x = [4 +/- sqrt(16 - 12) ] / 2

x = (4 +/- 2) / 2

x = 2 /2 = 1

or

x = 6/2 = 3

Question 4

(x - 4)^2 - 28 = 8                     Add 28 to both sides

(x -4)^2 - 28 + 28 = 8 + 28     Combine like terms on the left and right

(x - 4)^2 = 36                           Take the square root of both sides.

x - 4 = +/- 6

x - 4 = 6

x = 6 + 4

x = 10

x - 4 = - 6

x = -6 + 4

x = - 2

The two points which are solutions are

(10,0)(-2,0)

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: