Determine the linear factors of the quadratic function

Step-by-step explanation:

The linear terms are those that are multiplied together to give a quadratic.

It looks like they are (x + 3)(x - 1/2) = y These come from the roots as seen on the graph

The more general equation might be (x + 3)(2x - 1)

The y intersect is determined by letting x = 0

y_int = (0 + 3)(2*0 - 1)

y_int = 3 (-1)

y_int = -3

The point is (0,-3)

One more value should be tried.

Let x = 1

f(x) = (x + 3)(2x - 1)

f(1) = (1 + 3)(2*1 - 1)

f(1) = (4 ) * (2 - 1)

f(1) = 4 * 1

f(1) = 4

I went to all this just to show that a in the general quadratic = 1

y = a(x + 3)(2x - 1)

a calculates out to 1.

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1