Let a = x^2 plus 4. use a to find the solutions for the following equation: (x^2 plus. 4)^2 plus 32 = 12x^2 plus 48 which of the following are solutions for x

0 or +-2

Step-by-step explanation:

(x^2 + 4)^2 + 32 = 12x^2 + 48

=> x^4 + 8x^2 + 16 + 32 - 12x^2 - 48 = 0

=> x^4 - 4x^2 = 0

=> x^2(x^2 - 4) = 0

=> x^2 = 0 or 4

=> x = 0 or +-2

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

what? ?

what type of question is thiss

step-by-step explanation: