Match equivalent trigonometric ratios.

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cosθ

sinθ

cotθ

secθ

cscθ

tanθ

csc (90° - θ)
sin (90° - θ)
tan (90° - θ)
cos (90° - θ)
cot (90° - θ)
sec (90° - θ)

Hello from MrBillDoesMath!

csc (90° – x) = sec (x )

sin (90° – x) = cos (x )

tan (90° – x) = cot (x)

cos (90° – x) = sin (x )

cot (90° – x) = tan (x )

sec (90° – x) = csc (x)  

Thank you,

MrB    

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3