Bad a contains 3 white marbles and 2 red marbles. bag b contains 6 white marbles and 3 red marbles. a person draws one marble from each bag. find the probability that both marbles are white.
a) 2/5
b) 3/5
c) 9/14

The probability of drawing out a white marble from bag A is 3/5 since there are 3 white out of 3+2 = 5 total

Similarly, bag B has 6 white out of 6+3 = 9 total, so the probability of getting white here is 6/9 = 2/3

Multiply the two fractions: (3/5)*(2/3) = (3*2)/(5*3) = 6/15 = 2/5

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0