Igive 62 ! me..i am struggling with this question and my assignment is overdue already..

A)

The formula for the distance in a given time, is x = vt - 0.5gt^2

where x is the distance

v is the initial velocity, given as 64 ft/s

g is the acceleration due to gravity which is equal to 32 ft/s^2

t is the time

Now you have:

x = 64t - 0.5(32)t^2

Simplify:

x = 64t -16t^2

Rearrange this so the exponent is first:

h(t) = -16t^2 +64t

B) See attached picture:

C) Maximum height was 64 feet. It reached maximum height in 2 seconds and total time in the air was 4 seconds.

5

step-by-step explanation:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3