Hey guys! can you me how to solve number 16, 18, and 20. because i don’t understand how to solve this

Problem 16

Work Shown:

The exponent 41 divided by 4 leads to

41/4 = 10 remainder 1

The "remainder 1" means that

i^(41) = i^1 = i

The reason why I divided by 4 is because the pattern shown below

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

repeats itself over and over. So this is a block of four items repeated forever.

Problem 18

Work Shown:

Divide 3136 over 4 to get

3136/4 = 784 remainder 0

Therefore,

i^3136 = i^0 = 1

Problem 20

Work Shown:

Combine i^6*i^7 into i^13. We add the exponents here

Now divide by 4 to find the remainder

13/4 = 3 remainder 1

So, i^13 = i^1 = i

answer is 12345678900987654321234567890987654321

step-by-step explanation: