Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16

Integer 1 = 4

Integer 2 = 6

Step-by-step explanation:

If you have two unknown consecutive even integers, you could call them as follows:

Integer 1 = x

Integer 2 = x+2

Your question claims that the smaller added to two times the larger gives a sum of 16.

So

Integer 1 + 2*(Integer 2) = 16

x + 2*(x+2) = 16

x + 2x + 4 = 16

3x = 12

x = 4

Since x is 4, this is your smaller integer. Your larger integer, therefore, would be x + 2, or 4 + 2 = 6.

Integer 1 = 4

Integer 2 = 6

Hope this helps.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

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step-by-step explanation: