Arectangle is shown with length x plus 10 and width 2 x plus 5. the inside of the rectangle is shaded other than an unshaded square with length x plus 1 and width x plus 1.

Step-by-step explanation:

A rectangle is shown with length x plus 10 and width 2 x plus 5.

so the rectangle area = length * width

= (x + 10) * (2x + 5)

an unshaded square with length x plus 1 and width x plus 1

so the unshaded square area = (x + 1) * (x + 1)

the shaded area = rectangle area - square area

= (x + 10) * (2x + 5) - (x + 1) * (x + 1)

= (2x^2 + 20x + 5x + 50) - (x^2 + x + x + 1)

= x^2 + 23x + 49

Step-by-step explanation:

I am not sure what your question is asking so I will calculate areas of all three shapes:

Area of the rectange = length * width = (x + 10) * (2x + 5)

= 2x^2 + 25x + 50

Area of the unshaded square within the reactangle

= length * width

= (x + 1) * (x + 1)

= x^2 + 2x + 1

Shaded area inside the rectange

= Area of rectangle - Area of un-shaded square

= (2x^2 + 25x + 50) - (x^2 + 2x + 1)

= x^2 + 23x + 49

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

c

step-by-step explanation:

i think because what else can be a sample of every member