Janae and jerome each have m marbles. gwen has 4(m + 2) marbles. john has 8m + 4 marbles. if john has more marbles than janae, jerome, and gwen combined, how many marbles might janae and jerome each have? select each possible answer.
a.
janae and jerome each have 1 marble.
b.

janae and jerome each have 2 marbles.
c.

janae and jerome each have 3 marbles.
d.

janae and jerome each have 4 marbles.
e.

janae and jerome each have 5 marbles.

C, D, E

Step-by-step explanation:

The numbers of marbles are:

Janae, Jerome, and Gwen combined have

m + m + 4(m+2) = m + m +4m + 8 =6m + 8 marbles.

If John has more marbles than Janae, Jerome, and Gwen combined, then

So, possible answers are

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: