There are equal numbers of both red and black cards in a deck of 52.

1) what is the probability that i randomly select a red card?

2) if i keep the red card, what is the probability of me selecting another red card?

3) what is the probability of both of the above events happening in the order described?

A) there are 13 cards per suit and 4 suits, a total of 52 cards. So there are 13*2=26 red cards in a deck of 13*4=52, the odds of drawing a red card are 26/52=1/2=50%

B) Again outside knowledge is required, you name four suits but not their colors. Nonetheless, unless this is a very unusual deck, the diamonds and hearts are red, spades and clubs black. So that’s 2 red suits out of 4 suits. 2/4=1/2=50%

C) there are 2 black suits and 2 red suits. The odds of getting a red card are 2/(2+2)=2/4=1/2 or 50%

Each of those answers is a different way to figure the odds, they come out the same each time, as expected.

However, what if we assume that you mean… when drawing a 5 card poker hand? Or when Penn Jillette asks you “is this your card?”+ Or if you draw every card in the deck? Or if you are playing some macabre game in which you die if you draw the ace of spades but you may only stop drawing if you draw a red card?

There are myriad possible meanings to your question, I’ve just made the simplest assumption and given the odds on that… but my answer is woefully incomplete.

+ Hint, when Penn Jillette asks you “is this your card” your card is always the 3 of clubs. So… 0% chance.

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

nada

step-by-step explanation: