The number of customers rose from 118 on monday to 205 on tuesday. what is the percent increase to the nearest tenth of a percent

173.7%

Step-by-step explanation:

We can find the percent increase by putting 205 over 118. This equals 1.73728813559. This is only 1%, so now we will multiply it by 100. This is 173.728813559. This means that the percent increase is approximately 173.7%.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: