Arectangle has a length of 6x + 3 units and a width of 8 units.
part a: write a simplified expression for the area, in square units, of this rectangle.
another rectangle has a length of 4x + 2 units and a width of 12 units.
part b: are the areas of both rectangles the same? explain how you know.

Part A: 48x + 24 units^2

Part B: Yes; both rectangles have the same simplified expression for their area (48x + 24 units^2).

Step-by-step explanation:

First you should know what the formula for finding the area of a rectangle is. The formula is: length (l) times width (w).

Since you are given an expression for the length and the width, you can substitute these given values into the formula to form a simplified expression for Part A.

(length) * (width) ⇒ (6x + 3)(8)

Multiply to simplify this expression.

48x + 24 units^2 is the expression for the area of the rectangle.

To find the answer for Part B, do the same thing you did for Part A. Substitute the values for length and width of this other rectangle into the formula.

(length) * (width) ⇒ (4x + 2)(12)

Multiply to simplify this expression.

48x + 24 units^2

This rectangle has the same expression as the other rectangle, so this means that they must have the same area.

the answer will be b x² +x-1

step-by-step explanation: