Mathematics, 05.02.2020 00:01 user11883661
(-32)^0.8 i can’t find the answer no where
Answers: 3
![.\quad (-32)^{0.8}\\\\= (-32)^{\dfrac{8}{10}}\\\\= (-32)^{\dfrac{4}{5}}\\\\=\sqrt[5]{(-32)^4} \\\\=(-2)^4\\\\=16](/tpl/images/0502/1121/31f17.png)
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(-32)^0.8 i can’t find the answer no where...
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