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1) x² - 6x + 58 = 0

2) x² - 12x + 45 = 0

3) x² - 10x + 23 = 0

4) x² - 2x - 48 = 0

Step-by-step explanation:

1-4 The form the quadratic equation with its roots:

ax² + -b/a x + c/a = 0 ⇒ b is the sum of the roots and c is the product of the roots.

If the roots are irrational numbers or complex number then they are conjugate

Ex: 1] irrational ⇒ their sum and product are

      rational numbers

     2] complex (5 - 3i)(5 + 3i) ⇒ their sum and product are rational numbers

1) ∵ The first root is 3 + 7i ⇒ ∴ the second root is 3 - 7i

   ∵ their sum = 3 + 7i + 3 - 7i = 6

   ∵ their product = (3 + 7i)(3 - 7i) = 9 - 49i² = 9 + 49 = 58⇒(i² = -1)

∴ The equation⇒ x² - 6x + 58 = 0

2) ∵ The first root is 6 - 3i ⇒ ∴ the second root is 6 + 3i

   ∵ their sum = 6 - 3i + 6 + 3i = 12

   ∵ their product = (6 - 3i)(6 + 3i) = 36 - 9i² = 36 + 9 = 45⇒(i² = -1)

∴ The equation⇒ x² - 12x + 45 = 0

3) ∵ The first root is 5 + √2 ⇒ ∴ the second root is 5 - √2

   ∵ their sum = 5 + √2 + 5 - √2 = 10

   ∵ their product = (5 + √2)(5 - √2) = 25 - 2 = 23

∴ The equation⇒ x² - 10x + 23 = 0

4) ∵ The first root is -6 and the second root is 8

   ∵ their sum = -6 + 8 = 2

   ∵ their product = (-6)(8) = -48

∴ The equation⇒ x² - 2x - 48 = 0

5-8 Solving equations:

1) x² - 6x + 58 = 0

a = 1 , b = -6 , c = 58

x =

2) x² - 12x + 45 = 0

a = 1 , b = -12 , c = 45

x =

3) x² - 10x + 23 = 0

a = 1 , b = -10 , c = 23

x =

4) x² - 2x - 48 = 0 ⇒ using factorization

  (x - 8)(x + 6) = 0

  x - 8 = 0⇒ x = 8

  x + 6 = 0⇒ x = -6

answer: 5100 just subtract

step-by-step explanation: