when you use the distance formula, does it matter what point you choose as (x1 , y1) and what point you choose as (x2 , y2)? explain why or why not.

No.

Step-by-step explanation:

No,  as long as you  use the correct formula which is

√[(y2 - y1)^2 + (x2 - x1)^2].

If  for example the 2 points are (1,6) and (-2,-5) and

we let  (x1, y1) be (1, 6) and (x2,y2) be (-2,-5)  the length is  

√(-5-6)^2 + (-2-1)^2

= √(121 + 3) =  √130

and if it was the other way around the length  is

√((6--5)^2 + (1- -2)^2)  

=  √(121 + 9)

= √(130).

The differences are negative in one case and positive in the other but the squares are the same.

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61