Show the steps taken to complete the problems:

volume of a cylinder: 34m diameter and 27m height
use 3.14 for pi.

find the surface area of the cone. 8in. diameter and 7in. height.

find the lateral area of the square pyramid: 8in. base and 22in. slant

Volume cylinder = 24501.42 m³

The surface area of the cone = 151.5 in²

The lateral area of the square pyramid = 352 in²

Step-by-step explanation:

∵ The volume of the cylinder = area base × height

∵ Its base is a circle

∴ V = πr² × h = 3.14 × (34/2)² × 27 = 24501.42 m³

∵ The surface area of the cone = 1/2 perimeter base ×  Slant height + area base

∵ Its base is a circle

∴ S.A = (1/2) × 2πr × l + πr²

∵ The slant height =

∴ S.A = 3.14 × (8/2) × √65 + 3.14 × (8/2)² = 151.5 in²

∵ The lateral area of the square pyramid = 1/2 perimeter base × slant height

∵ Its base is a square

∴ L.A = 1/2 × (8 × 4) × 22 = 352 in²

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116