Find the product. (2 x^2 - 4 x + 1)(5 x - 7)

10x^3 - 34x^2 + 33x -7

Step-by-step explanation:

You multiply the whole 1st equation by EACH of the terms in the second like this:

(2x^2 - 4x + 1)(5x - 7)=

10x^3 - 20x^2 + 5x - 14x^2 + 28x -7

Now combine like terms:

10x^3 - 34x^2 + 33x -7

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.