Locating zeros of polynomial functions ! pl will mark most brainiest

Option 1. (-1, 1 ) is the correct option.

Step-by-step explanation:

The given polynomial function is

To find the real zeros of any polynomial we follow the procedure as below

First we find p/q where p represents the factors of constant term of the polynomial and q represents the factors of the coefficient of highest degree term of the expression.

So factors will be = p/q = ± factors of 2/ ± factors of 2

                                      = ±1, ±2/±1, ±2

So the probable factors are ±1, ±2

Now by putting the values of x in the polynomial

For x = 1

f(x) = 2 - 1 + 1 - 2 = 0

Therefore (x-1) is a factor.

For x = -2

f(x) = 2×16 + 8 -2 -2 = 36

So its not the factor.

For x = -1

f(x) = 2 + 1 - 1 - 2 = 0

Therefore for x = -1 and x= 1 f(x) is zero.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

answer4 to the second power is 16

and 4 to the third power is 64,