Amodel rocket is launched with an initial upward velocity of 65/ms . the rocket's height h (in meters) after t seconds is given by the following. h=65t-5t^2 find all values of t for which the rocket's height is 25 meters. round your answer(s) to the nearest hundredth. (if there is more than one answer, use the "or" button.) ground h

➷

Minus 56 and add to both sides

Divide by 5 to get

Substitute these values into the quadratic equation to give you the answers:

0.40s and 12.60s

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↬ Hannah ♡

t≈0.40

t≈12.6

Step-by-step explanation:

h=65t-5t^2

Let h = 25

25=65t-5t^2

Subtract 25 from each side

25-25=-25 +65t-5t^2

0 = -5t^2 +65t -25

Using the quadratic formula

where a =- 5 b= 65 and c=-25

-b ± sqrt (b^2 -4ac)

2a

-65 ± sqrt (65^2 -4(-5)(-25))

2(-5)

-65 ± sqrt (4225 -250))

-10

-65 ± sqrt (3975))

-10

t≈0.39672

t≈12.603

Rounding to the nearest hundredth

t≈0.40

t≈12.6

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure