What is a quart of function with only the two real zeros given? x = -4 and x = -1

f(x) =

Step-by-step explanation:

∵ The zeroes of the function are x = -4 and x = -1

∵ x + 4 = 0 and x + 1 = 0

∴ The factors of the function are (x + 4) (x + 1)

∴ The function = (x + 4) (x + 1)

∴ f(x) =

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

step-by-step explanation:

this is not a question