1/√t(x^2-3)
1-3x/x
-2/x
Mathematics, 25.11.2019 18:31 alliaespino
if f(x) = x^2 - 3 and g(x) = 1/√x , find (f °g)(x).
1/√t(x^2-3)
1-3x/x
-2/x
1/(x-3)
Answers: 3
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You know the right answer?
if f(x) = x^2 - 3 and g(x) = 1/√x , find (f °g)(x).
1/√t(x^2-3)
1-3x/x
-2/x
1/√t(x^2-3)
1-3x/x
-2/x
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