in triangle abc segment de is parallel to the side ac . (the endpoints of segment de lie on the sides ab and bc respectively). find the ratio ad: bd, if ac: de=55: 28

AD/DB = 27/28

Step-by-step explanation:

We are to find AD: BD

We can solve this problem using proportions.  Putting the larger triangle over the smaller triangle and using similar triangles we know

AB           AC

-------- = -----------

DB           DE

AB           55

-------- = -----------

DB           28

We can rewrite

AB as AD + DB since it is a line

AD +DB           55

----------- = -----------

DB               28

Using cross products

28 (AD +DB) = 55 DB

Distribute

28 AD +28DB = 55 DB

Subtract 28 DB from each side

28 AD +28DB- 28DB = 55 DB -28DB

28AD = 27DB

We want the ratio AD/DB

Divide by DB

28AD/DB = 27DB/DB

28AD/DB = 27

Divide by 28

28AD/28DB = 27/28

AD/DB = 27/28

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: