part a: find the zeros if the function g(x)=(x^2-1)(x+3)
part b: graph the function g(x)

The zeroes are x = -3 , -1 and 1.

Step-by-step explanation:

(x^2 - 1)(x + 3) = 0

(x - 1)(x + 1) (x + 3) = 0

x- 1 = 0 gives x = 1

x + 1 = 0 gives x = -1

x + 3 = 0 gives x = -3.

The graph will rise from the left and will have 2 loops and pass through the x axis at x = -3 , x = -1 and x = 1.

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.