Suppose a spider was able to create one thread that would extend from the top-right back corner of a room to the bottom-left front corner. approximately how long would that thread need to be for the room below to the nearest tenth of a foot? the path of the spider's thread is shown with a dotted line. (hint: you will use the pythagorean theorem twice.)

33.3 feet to the nearest tenth.

Step-by-step explanation:

WE first need to find the length of the diagonal (d) across the bottom of the room.

d^2  = 30^2 + 12^2 = 1044.

Now applying Pythagoras theorem to the triangle whose hypotenuse (h)  is the path of the spider:

h^2 = d^2 + 8^2

= 1044 + 64

= 1108

h = √1108

= 33.3 feet.

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula