Δabc has vertices a(-4,6), b (-6, -4), and c (2,-2)
the following transformation defines δ a'''b'''c''':
δa'''b'''c'''= in image, multiple choice.

  A'''(0, -6), B'''(-1, -1), C'''(3, -2)

Step-by-step explanation:

The first transformation is dilation by a factor of 1/2, so each coordinate is multiplied by 1/2.

  A' = (1/2)A = (-4, 6)/2 = (-2, 3)

The next transformation is translation, which adds (2, 3) to the coordinates.

  A'' = (-2, 3) + (2, 3) = (0, 6)

The final transformation reflects across the x-axis, which negates the y-coordinate.

  A''' = (0, -1·6) = (0, -6) . . . . . matches the 3rd choice for A'''

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Taken together, the transformations map (x, y) as follows:

  (x, y) ⇒ (x/2 +2, -(y/2 +3))

Then

  B''' = (-6/2 +2, -(-4/2 +3)) = (-1, -1) . . . matches 1st choice for B'''

  C''' = (2/2 +2, -(-2/2 +3)) = (3, -2) . . . matches 3rd choice for C'''

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: