Idon't know how to do this.
3. apply your knowledge of factoring and zero product property to write a quadratic function when given -2 and 2/3 as the zeros. (show all work for full credit)

3x^2 +4x-4

Step-by-step explanation:

We know the zeros are  -2 and 2/3

Using the zero product property

(x- -2) (x -2/3) = 0

(x+2) (x-2/3) = 0

We want to write the function, so we need to FOIL

first x*x = x^2

outer: -2/3x

inner: 2x

last: -4/3

Add together

x^2 -2/3x +2x -4/3 =0

x^2 -2/3x+6/3x -4/3 =0

x^2 +4/3x - 4/3 =0

We can multiply by any constant and it will still give us the same zeros

I will multiply by 3 to get rid of the fractions

3(x^2 +4/3x - 4/3) =0*3

3x^2 +4x-4 = 0

-6 is the correct option from the above given options

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.