Gary is 8 years older than his brother. six years ago gary was three times as old as his brother. how old are they now?

We can set two equations to solve the question:

Let Gary's age be x and his brother's age be y.

As Gary is 8 years older:

x+8 = y

x = y-8...(1)

Six years ago Gary was three times as old as his brother:

x-6=3(y-6)...(2)

Put (1) into (2)

y-8-6 = 3y -36

-2y = -36+14

y = -22/-2

y=11

His brother is 11 years old, while the age of Gary:

11+8=19

Hope it helps!

step-by-step explanation:

sry but any answer choices