Use the discriminate to determine the number and the nature of the solutions of the giving equation
2x^2+ 5x+7=0

Since b^2 -4ac = -31 we have 2 complex roots

Step-by-step explanation:

2x^2+ 5x+7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =2   b=5 and c=7

(5)^2 - 4(2)(7)

25 - 56

-31

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = -31 we have 2 complex roots

20%

step-by-step explanation: