Suppose you are flying a kite that is 50 feet long. while flying there is a constants gust of wind that blows the kite to angle of 60 with the ground .how high, in feet is the kite above the ground?

The  kite forms a right angled triangle with hypotenuse of 50 ft. The height of the kite above the ground is the opposite of 60° angle.

Using the sine rule, Sin 60 = Height of the kite above the ground/Hypotenuse

Therefore, Height of the kite above the ground = Hypotenuse*Sin 60 = 50 *Sin 60 = 43.3 ft

I found this same question and answer (that was verified) on another post

Hope that helps! Happy v-day fam!

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: