What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table? drag and drop the values into the boxes to show the relative frequencies.

.25             .75

.44            .56

Step-by-step explanation:

To find the relative frequency, we take the part over the total.

Since this  is a relative frequency table, the total for each row is 1

Group 1 A  = 15/ (15+45) = 15/60 = .25

Group 1 B = 45/(15+45) = 45/60 = .75

Group 2 A = 20 /(20+25) = 20/45 =.44

Group 2B = 25/(20+25) = 25/45 =.56

5050

hope this !

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.