The solutions to a certain quadratic equation are x = -4 and x = 3. write the equation in standard form below.
+x =0

Quadratic equation is x²  + x - 12  = 0.

Step-by-step explanation:

Given : The solutions to a certain quadratic equation are x = -4 and x = 3.

To find : Write the equation in standard form below.

Solution : We have given x = -4 and x = 3.

We can write the solution as x +4 = 0

x - 3 = 0.

Both the solution have GCF is 1

Then solution are (x +4)(x -3) = 0.

On distributing x over (x-3) and +4 over (x-3).

x(x-3) +4(x-3) = 0.

x² -3x +4x -12 = 0.

x²  + x - 12  = 0.

Then  quadratic equation is x²  + x - 12  = 0.

Therefore, Quadratic equation is x²  + x - 12  = 0.

4th option is correct xy=-10

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δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)