Write the slope-intercept form of the equation of the line that is perpendicular to ab and passes through point x. show all work for full credit.

y = 12/5x +22

Step-by-step explanation:

The slope of the line containing (-10,8) and (2,3) can be found using

m = (y2-y1)/(x2-x1)

   = (3-8)/(2--10)

   = -5/(2+10)

   = -5/12

We want a line that is perpendicular, so we take the negative reciprocal

m perpendicular = - (-12/5)  = 12/5

We want it through the point (-5,10)

We will use point slope form to get the line

y-y1 = m(x-x1)

y - 10 = 12/5(x--5)

y- 10 = 12/5 (x+5)

Distribute

y-10 = 12/5 x +12

Add 10 to each side

y-10+10 = 12/5x +12+10

y = 12/5x +22

This is in slope intercept form

The slope-intercept form : y = 12/5 x + 22

Step-by-step explanation:

Line AB: Slope = (8 - 3)/(-10 - 2) = 5/-12 = -5/12

Perpendicular , slope is opposite and reciprocal so slope of the line  that is perpendicular to AB is equal = 12/5

Passes through Point X(-5, 10)

y - 10 = 12/5(x + 5)

y - 10 = 12/5 x + 12

y = 12/5 x + 22

The slope-intercept form : y = 12/5 x + 22