Suppose that to make the golf team you need to score no more than 74 on average over 5 games if you scored 77,71,77, and 67 in your first 4 games what is the highest score you can shoot in your 5th game and still make the team

≤ 78

Step-by-step explanation:

By setting up an inequality and making 'x' the highest score you can shoot in your 5th game, you can solve for the value of 'x'.  Average is the sum of all the scores divided by the number of games:

The first step to solving for 'x' is to multiply both sides of the inequality by 5:

Now, subtract 292 from both sides:

292 + x - 292 ≤ 370-292 or x ≤ 78

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

7/2

(decimal: 3.5)

welcome ; )

step-by-step explanation: