Rachel deposited $200 into an account that earns 6% interest, compound twice a year for 10 years. a=p(1+ r n ) n

She will have $361.22 after 10 years

Step-by-step explanation:

For the formula A = P(1 + r/n)^(nt),

r      needs to be input as a decimal

n     is the number of times the interest is compounded annually

t      is how many years the interest compounded

P     is the initial principle

A     is the final amount of money in the account

For this problem...

r = 0.06   (6% as a decimal)

n = 2        (compounded twice a year)

t = 10       (the money was left in for 10 years)

P = 200  (the initial principle)

A = final amount, we need to solve for this

Plug these values into the equation and solve for A

A = P(1 + r/n)^(nt)   becomes      A = 200(1 + 0.06/2)^(2x10)

    which simplifies to    A = 200(1.03)^20

   which simpifies to      A = $361.22

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841