An ice cream cone has a height of 16 cm and a diameter of 4 centimeters what is the volume of ice cream that can be contained within the cone

67.014

Step-by-step explanation:

V = π r^2 (h/3)

(Volume equals pi r squared, h over 3)

Diameter is 4, so the radius is half of that = 2

Plug in the numbers

V = π (2^2) (16/3)

V = π (4) (5.333)

V = 3.14 x 4 = 12.566

V = 12.566 x 5.333

V = 67.014

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

what "following statement"?

step-by-step explanation: