In mathematics competition, the winner won $100 more than twice the amount won by the runner-up. how much money did the runner-up win if both of them won $2,350 altogether

$750

Step-by-step explanation:

Since there are two people who won prize money and the total amount won is $2,350, we can set up an equation based on the verbal descriptions to assign a variable and solve.

Let 'x' = the amount won by the runner-up

Since the winner won '$100 more than twice the amount won by the runner-up':  winner = 2x + 100

The sum of the amount is $2,350, so:

x + (2x + 100) = 2350 or 3x + 100 = 2350

Subtract 100 from both sides:  3x + 100 - 100 = 2350 - 100 or 3x = 2250

Divide by 3 on both sides: 3x/3 = 2250/3

Solve for x:  x = $750

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]