Let f (x) = –x2 + 3x + 1 and g(x) = 2x. look at the composition shown. what is the error in the student’s work? f (g (x)) = –(2x)2 + 3x + 1 = –4x2 + 3x + 1

The error he did was that in place of 3(2x) he wrote 3x

i.e. the error was in the second term of the expression.

Step-by-step explanation:

We are given that:

f (x) = -x² + 3x + 1 and g(x) = 2x

f(g(x))=f(2x)

        = -(2x)²+3(2x)+1

       = -4x²+6x+1

But, student wrote it as:

f (g (x)) = -(2x)² + 3x + 1 = -4x² + 3x + 1

On comparing our work with the students work, we see that

The error he did was that in place of 3(2x) he wrote 3x

i.e. the error was in the second term of the expression.

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i will answer your question though.

i never tried church's

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