Ted has collected an average of 52 coins per month from january to october. the balance of his coin collection at the end of march was 2018 coins. find the number of coins ted had at the end of october.
a) 2382
b) 2434
c) 2486
d) 2538

Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Number of coins at the end of March = 2018 coins

Average of coins per month from January to October = 52

Total sum of coins from April to October will be

So, the number of coins Ted had at the end of October is given by

Hence, there are 2382 coins at the end of October.

Therefore, Option 'A' is correct.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

c

step-by-step explanation: