Evelyn is making a candy that contains 25% dark chocolate and the rest milk chocolate. the candy has 3 pounds of milk chocolate.

part a: write an equation using one variable that can be used to find the total number of pounds of dark chocolate and milk chocolate in the candy. define the variable used in the equation and solve the equation. hint: 0.25x represents the number of pounds of dark chocolate in the candy. (5 points)

part b: how many pounds of dark chocolate are present in the candy? show your work. (5 points)

The sum of the percentages of milk and dark chocolate needs to equal 100%.

Since dark chocolate is 25%, then milk chocolate must be 75%

Now we can set up a proportion:

75% = 3 lbs

25% = X lbs

Dark chocolate =  (3 x 25%) / (75% x X) = 1 lb

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

20%

step-by-step explanation: