Solve the system of equations algebraically.
3x-3y=6
6x-7y=8

a.(5,5)
b. many solutions
c. no solution
d. (6,4)

The correct option is d.

Step-by-step explanation:

The given equations are

              ....(1)

               ..... (2)

Multiply equation (1) by  by 2, to make same coefficient of x.

              ....(3)

Subtract equation (2) form equation (3).

Substitute this value in equation (1),

The solution of the given system of equation is (6,4).

Therefore the correct option is d.

Choice d is correct answer.

Step-by-step explanation:

We have given two equation.

3x-3y = 6                eq(1)

6x-7y = 8                eq(2)

We have to find the solution of given equations.

Multiplying by both sides of eq(1) by 2, we have

2(3x-3y) = 2(6)

6x-6y = 12                  eq(3)

Subtracting eq(3) to eq(2) , we have

6x-6y -(6x-7y) = 12-8

6x-6y-6x+7y = 4

Adding like terms, we have

6x-6x+7y-6y = 4

y = 4

Putting the value of y in eq(1), we have

3x-3(4) = 6

3x-12 = 6

Adding 12 to both sides of above equation, we have

3x-12+12= 6+12

3x = 18

Dividing by 3 to both sides of above equation , we have

3x/3 = 18/3

x = 6

Hence, the solution set is (6,4).

sorry, i don't know i just need points, i'm new here. chao

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: