Work out the length of am, then find the area of the triangle.
* refer to image below*

see explanation

Step-by-step explanation:

ΔABC is isosceles and AM is the perpendicular bisector to BC, hence

BM = MC = 4 cm

Using Pythagoras' identity on ΔABM, then

AB² = AM² + BM², that is

7² = AM² + 4²

49 = AM² + 16 ( subtract 16 from both sides )

33 = AM² ( take the square root of both sides )

AM =

The area (A) of ΔABC is found using

A = bh ( b is the base BC and h the height AM )

A = × 8 × = 4 cm² ≈ 23 cm²

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: