There are 3 consecutive even integers .if twice the first integer added to the third is 268,222, find all three integers

89406, 89408 and 89410.

Step-by-step explanation:

Let n be the any even integer.

So n+2 will be 2nd even integer and n+4 will be 3rd even integer.

We are told that twice the first integer added to the third is 268,222.

Twice the first integer will be 2*n.

We can represent this information in an equation as:

Let us subtract 4 from both sides of our equation.

Let us divide both sides of our equation by 3.

Therefore, our 1st even integer will be 89406.

2nd even integer = n+2

3rd even integer = n+4

Therefore, our three consecutive even integers will be 89406, 89408 and 89410.